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Right triangle ABC with altitude d

Source: Canadian Repêchage 2009: Problem 2

April 25, 2014
geometryPythagorean Theoremgeometry proposedtrigonometry

Problem Statement

Triangle ABCABC is right-angled at CC with AC=bAC = b and BC=aBC = a. If dd is the length of the altitude from CC to ABAB, prove that 1a2+1b2=1d2\dfrac{1}{a^2}+\dfrac{1}{b^2}=\dfrac{1}{d^2}