MathDB
Problems
Contests
National and Regional Contests
Brazil Contests
Brazil National Olympiad
1993 Brazil National Olympiad
5
F(2x+1) = 3f(x) + 5
F(2x+1) = 3f(x) + 5
Source: Problem 5, Brazil MO 1993
March 18, 2006
function
logarithms
algebra
functional equation
algebra proposed
Problem Statement
Find at least one function
f
:
R
ā
R
f: \mathbb R \rightarrow \mathbb R
f
:
R
ā
R
such that
f
(
0
)
=
0
f(0)=0
f
(
0
)
=
0
and
f
(
2
x
+
1
)
=
3
f
(
x
)
+
5
f(2x+1) = 3f(x) + 5
f
(
2
x
+
1
)
=
3
f
(
x
)
+
5
for any real
x
x
x
.
Back to Problems
View on AoPS