MathDB
AE = CF, BF = EF, <EAB= <BAC,<FAC =<CAD (2019 Romania District VII p2)

Source:

May 21, 2020
geometryanglesequal anglesequal segments

Problem Statement

Consider DD the midpoint of the base [BC][BC] of the isosceles triangle ABC in which ∠BAC<90o\angle BAC < 90^o. On the perpendicular from BB on the line BCBC consider the point EE such that ∠EAB=∠BAC\angle EAB= \angle BAC, and on the line passing though CC parallel to the line ABAB we consider the point FF such that FF and DD are on different side of the line ACAC and ∠FAC=∠CAD\angle FAC = \angle CAD. Prove that AE=CFAE = CF and BF=EFBF = EF
Back to ProblemsView on AoPS