MathDB
Geometry

Source: RMO 2016 Karnataka Region P5

October 16, 2016
geometry

Problem Statement

Let ABCABC be a right-angled triangle with B=90\angle B=90^{\circ}. Let II be the incentre if ABCABC. Extend AIAI and CICI; let them intersect BCBC in DD and ABAB in EE respectively. Draw a line perpendicular to AIAI at II to meet ACAC in JJ, draw a line perpendicular to CICI at II to meet ACAC at KK. Suppose DJ=EKDJ=EK. Prove that BA=BCBA=BC.