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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
642
Today's calculation of Integral 642
Today's calculation of Integral 642
Source:
August 22, 2010
calculus
integration
trigonometry
calculus computations
Problem Statement
Evaluate
∫
0
π
6
(
tan
2
2
x
)
cos
2
x
+
2
(
cos
2
x
)
cos
2
x
d
x
.
\int_0^{\frac{\pi}{6}} \frac{(\tan ^ 2 2x)\sqrt{\cos 2x}+2}{(\cos ^ 2 x)\sqrt{\cos 2x}}dx.
∫
0
6
π
(
cos
2
x
)
cos
2
x
(
tan
2
2
x
)
cos
2
x
+
2
d
x
.
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