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Today's calculation of Integral 615

Source:

June 28, 2010
calculusintegrationlogarithmsderivativecalculus computations

Problem Statement

For 0≤a≤20\leq a\leq 2, find the minimum value of ∫02∣11+ex−11+ea∣ dx.\int_0^2 \left|\frac{1}{1+e^x}-\frac{1}{1+e^a}\right|\ dx.
2010 Kyoto Institute of Technology entrance exam/Textile e.t.c.
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