For every positive integer n, f(2n+1)=2f(2n), f(2n)=f(2n−1)+1, and f(1)=0. What is the remainder when f(2005) is divided by 5?<spanclass=′latex−bold′>(A)</span>0<spanclass=′latex−bold′>(B)</span>1<spanclass=′latex−bold′>(C)</span>2<spanclass=′latex−bold′>(D)</span>3<spanclass=′latex−bold′>(E)</span>4