MathDB
Romania District Olympiad 2001 - Grade X

Source:

March 16, 2011
logarithmsalgebra proposedalgebra

Problem Statement

Solve the equation:
2lgx+8=(x8)1lg22^{\lg x}+8=(x-8)^{\frac{1}{\lg 2}}
Note: lgx=log10x\lg x=\log_{10}x.
Daniel Jinga