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A, P, Q, O are concyclic if BP : PQ : QC = b : a : c

Source: brazilian tst 01

March 16, 2005
geometrycircumcirclegeometric transformationreflectiongeometry solved

Problem Statement

Let ABCABC be a triangle with circumcenter OO. Let PP and QQ be points on the segments ABAB and ACAC, respectively, such that BP:PQ:QC=AC:CB:BABP : PQ : QC = AC : CB : BA. Prove that the points AA, PP, QQ and OO lie on one circle. Alternative formulation. Let OO be the center of the circumcircle of a triangle ABCABC. If PP and QQ are points on the sides ABAB and ACAC, respectively, satisfying BPPQ=CABC\frac{BP}{PQ}=\frac{CA}{BC} and CQPQ=ABBC\frac{CQ}{PQ}=\frac{AB}{BC}, then show that the points AA, PP, QQ and OO lie on one circle.