1986 MMPC , Part 2 = Michigan Mathematics Prize Competition
Source:
October 18, 2022
MMPCalgebrageometrycombinatoricsnumber theory
Problem Statement
p1. is constructed from equilateral by choosing on , on and on so that , where is a number between and .
(a) Show that is also equilateral.
(b) Determine the value of that makes the area of equal to one half the area of .
p2. A bowl contains some red balls and some white balls. The following operation is repeated until only one ball remains in the bowl:
Two balls are drawn at random from the bowl. If they have different colors, then the red one is discarded and the white one is returned to the bowl. If they have the same color, then both are discarded and a red ball (from an outside supply of red balls) is added to the bowl.
(Note that this operation—in either case—reduces the number of balls in the bowl by one.)
(a) Show that if the bowl originally contained exactly red ball and white balls, then the color of the ball remaining at the end (i.e., after two applications of the operation) does not depend on chance, and determine the color of this remaining ball.
(b) Suppose the bowl originally contained exactly red balls and white balls. Show again that the color of the ball remaining at the end does not depend on chance and determine its color.
p3. Let , and be three consecutive positive integers, with
(a) Show that cannot be the square of an integer.
(b) Show that cannot be the square of an integer.
(c) Show that cannot be the square of an integer.
p4. Consider the system of equations
(a) Show (algebraically or graphically) that there are two or more solutions in real numbers and .
(b) The graphs of the two given equations intersect in exactly two points. Find the equation of the straight line passing through these two points of intersection.
p5. Let and be positive integers. An rectangle is tiled with unit squares. Let denote the number of rectangles formed by the edges of these unit squares. Thus, for example, .
(a) Find .
(b) Find .
(c) Find, with justification, a formula for .
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