MathDB
4 Variable Inequality

Source: Iran TST 2015 - second exam - first day problem 1

June 12, 2015
inequalities unsolvedinequalities

Problem Statement

a,b,c,da,b,c,d are positive numbers such that cyc1ab=1\sum_{cyc} \frac{1}{ab} =1. Prove that : abcd+168(a+c)(1a+1c)+8(b+d)(1b+1d)abcd+16 \geq 8 \sqrt{(a+c)(\frac{1}{a} + \frac{1}{c})}+8\sqrt{(b+d)(\frac{1}{b}+\frac{1}{d})}