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19
AJHSME 1991 Problem 19
AJHSME 1991 Problem 19
Source:
June 24, 2011
Problem Statement
The average (arithmetic mean) of
10
10
10
different positive whole numbers is
10
10
10
. The largest possible value of any of these numbers is
(A)
10
(B)
50
(C)
55
(D)
90
(E)
91
\text{(A)}\ 10 \qquad \text{(B)}\ 50 \qquad \text{(C)}\ 55 \qquad \text{(D)}\ 90 \qquad \text{(E)}\ 91
(A)
10
(B)
50
(C)
55
(D)
90
(E)
91
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