MathDB
3 variable inequality

Source: Korea National 2013 #2

November 10, 2013
inequalitiesalgebra

Problem Statement

Let a,b,c>0 a, b, c>0 such that ab+bc+ca=3 ab+bc+ca=3 . Prove that cyc(a+b)3(2(a+b)(a2+b2))1312 \sum_{cyc} { \frac{ (a+b)^{3} }{ {(2(a+b)(a^2 + b^2))}^{\frac{1}{3}}} \ge 12 }