MathDB
parallelogram

Source: Poland 2001

November 9, 2004
geometryparallelogramgeometric transformationreflectionratioanalytic geometryangle bisector

Problem Statement

Let ABCDABCD be a parallelogram and let KK and LL be points on the segments BCBC and CDCD, respectively, such that BKAD=DLABBK\cdot AD=DL\cdot AB. Let the lines DKDK and BLBL intersect at PP. Show that DAP=BAC\measuredangle DAP=\measuredangle BAC.