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Prove that |RP| = |PD|

Source: VAIMO 1, German Pre-TST 2010

July 16, 2011
geometryrhombusgeometry unsolved

Problem Statement

The quadrilateral ABCDABCD is a rhombus with acute angle at A.A. Points MM and NN are on segments AC\overline{AC} and BC\overline{BC} such that DM=MN.|DM| = |MN|. Let PP be the intersection of ACAC and DNDN and let RR be the intersection of ABAB and DM.DM. Prove that RP=PD.|RP| = |PD|.