MathDB

Geometry question

Source:

April 11, 2017

geometry

Problem Statement

P

,

Q

,

R

and

S

are (distinct) points on a circle.

PS

is a diameter and

QR

is parallel to the diameter

PS

.

PR

and

QS

meet at

A

. Let

O

be the centre of the circle and let

B

be chosen so that the quadrilateral

POAB

is a parallelogram. Prove that

BQ

=

BP

.

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