MathDB
Logs and Trig

Source:

May 11, 2006
trigonometrylogarithms

Problem Statement

Given that log10sinx+log10cosx=1\log_{10} \sin x + \log_{10} \cos x = -1 and that log10(sinx+cosx)=12(log10n1)\log_{10} (\sin x + \cos x) = \textstyle \frac{1}{2} (\log_{10} n - 1), find nn.