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0511 x^3 - y^3 = 2005(x^2 - y^2) 5th edition Round 1 p1

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May 6, 2021
number theory5th edition

Problem Statement

Find all pairs of positive integers x,yx, y such that x3−y3=2005(x2−y2)x^3 - y^3 = 2005(x^2 - y^2).
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