MathDB
Angle chasing in triangle

Source: Canada 1998

March 4, 2006
trigonometrygeometrycircumcircletrig identitiesLaw of Sinesgeometry unsolved

Problem Statement

Let ABCABC be a triangle with BAC=40\angle{BAC} = 40^{\circ} and ABC=60\angle{ABC}=60^{\circ}. Let DD and EE be the points lying on the sides ACAC and ABAB, respectively, such that CBD=40\angle{CBD} = 40^{\circ} and BCE=70\angle{BCE} = 70^{\circ}. Let FF be the point of intersection of the lines BDBD and CECE. Show that the line AFAF is perpendicular to the line BCBC.