MathDB
2014 Chile Classification / Qualifying NMO Seniors XXVI

Source:

October 15, 2021
algebrageometrycombinatoricsnumber theorychilean NMO

Problem Statement

p1. For a positive integer, let's call <a><a> the number obtained by multiplying each figure of a by 22 and writing the numbers thus obtained. For example <126>=2412<126> = 2412 and <809>=16018<809> = 16018. Prove that it is not possible find two different positive integers aa and bb such that <a>=<b><a> = <b>.
p2. In how many ways is it possible to cut a graph paper of 6×66\times 6 starting at the bottom of the paper and working to the top if it can only be cut on the lines of the grid, the two pieces in which it is divided must be equal and it can't be cut down (see figure)? https://cdn.artofproblemsolving.com/attachments/2/1/c9d6a5f0cf7230aff23cde16fd5308e08eac7e.png
Note: Two pieces are considered the same if you can place one over the other and they fit perfectly.
p3. In an equilateral triangle ABCABC with side 22, side ABAB is extended to a point DD so that BB is the midpoint of ADAD. Let EE be the point on ACAC such that ADE=15o\angle ADE = 15^o and take a point FF on ABAB so that EF=EC|EF| = |EC|. Determine the area of the triangle AFEAFE.
p4. For each positive integer nn we consider S(n)S (n) as the sum of its digits. For example S(1234)=1+2+3+4=10S (1234) = 1 + 2 + 3 + 4 = 10. Calculate S(1)S(2)+S(3)S(4)+...S(2012)+S(2013)S(2014)S (1)- S (2) + S (3)- S (4) +...- S (2012) + S (2013)- S (2014)
p5. Given 102102 points on a circle, next to one of them is written a 1 1 and next to each other a 00. The allowed operation consists of choosing a point that has a 11 and change the number of that point, and also the number of its two neighbors, the one on the left and on the right (where there is a 1 1, write 00 and where there is a 00 is written 1 1). Show that it is impossible, with permitted operations, to achieve that all the points have a 00.
p6. Consider a convex figure PP in the plane. For a point ZZ of the plane outside the figure we denote by Z,P|Z, P| the smallest length of the segments that join ZZ with some point of PP. Consider a line LL that does not intersect the figure PP, two points X,YX, Y over LL, and MM the midpoint between XX and YY. Prove that X,P+Y,P2M,P\frac{|X, P| + |Y, P|}{2} \ge |M, P|.
PS. Seniors P3, P4 were also proposed as [url=https://artofproblemsolving.com/community/c4h2690804p23355868]Juniors P3, easier P4.