MathDB
Today's calculation of Integral 700

Source: created by kunny

June 3, 2011
calculusintegrationtrigonometrycalculus computations

Problem Statement

Evaluate ∫0πx2cos⁡2x−xsin⁡x−cos⁡x−1(1+xsin⁡x)2dx\int_0^{\pi} \frac{x^2\cos ^ 2 x-x\sin x-\cos x-1}{(1+x\sin x)^2}dx
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