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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
616
Today's calculation of Integral 616
Today's calculation of Integral 616
Source:
July 1, 2010
calculus
integration
logarithms
calculus computations
Problem Statement
Evaluate
∫
1
3
ln
(
x
+
1
)
x
2
d
x
\int_1^3 \frac{\ln (x+1)}{x^2}dx
∫
1
3
x
2
l
n
(
x
+
1
)
d
x
.2010 Hirosaki University entrance exam
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