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2015 Algebra #2: Partial Fraction Decomposition

Source:

March 28, 2015
algebrapartial fractions

Problem Statement

The fraction 12015\tfrac1{2015} has a unique "(restricted) partial fraction decomposition'' of the form 12015=a5+b13+c31,\dfrac1{2015}=\dfrac a5+\dfrac b{13}+\dfrac c{31}, where aa, bb, and cc are integers with 0a<50\leq a<5 and 0b<130\leq b<13. Find a+ba+b.