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Many angle conditions

Source: Oral Moscow geometry olympiad 2023 10-11.6

April 20, 2023
geometry

Problem Statement

Points C1C_1 and C2C_2 lie on side ABAB of triangle ABCABC, where the point C1C_1 belongs to the segment AC2AC_2 and ACC1=BCC2\angle ACC_1= \angle BCC_2. On segments CC1CC_1 and CC2CC_2 points AA' and BB' are taken such that CAA=CBB=C1CC2\angle CAA'= \angle CBB' = \angle C_1CC_2. Prove that the center of the circle (CAB)(CA'B') lies on the perpendicular bisector of the segment ABAB.