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6
Problem 6, Fall 2003 , MS and HS
Problem 6, Fall 2003 , MS and HS
Source:
June 23, 2011
logarithms
Problem Statement
Evaluate:
1
log
2
(
1
6
)
−
1
log
3
(
1
6
)
−
1
log
4
(
1
6
)
\frac{1}{\log_2 (\frac{1}{6})} - \frac{1}{\log_3 (\frac{1}{6})} - \frac{1}{\log_4 (\frac{1}{6})}
lo
g
2
(
6
1
)
1
−
lo
g
3
(
6
1
)
1
−
lo
g
4
(
6
1
)
1
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