Parallelogram
Source: AIME 2009I Problem 4
March 18, 2009
geometryparallelogramratioAMCAIMErectangleanalytic geometry
Problem Statement
In parallelogram , point is on so that \frac{AM}{AB} \equal{} \frac{17}{1000} and point is on so that \frac{AN}{AD} \equal{} \frac{17}{2009}. Let be the point of intersection of and . Find .