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x^2+y^2+25z^2=6xz+8yz and 3x^2+2y^2+z^2=240 (Greece Juniors 2019 p1)

Source:

March 16, 2020
system of equationsalgebra

Problem Statement

Find all triplets of real numbers (x,y,z)(x,y,z) that are solutions to the system of equations x2+y2+25z2=6xz+8yzx^2+y^2+25z^2=6xz+8yz 3x2+2y2+z2=240 3x^2+2y^2+z^2=240