The greatest integer that will divide 13,511, 13,903, and 14,589 and leave the same remainder is<spanclass=′latex−bold′>(A)</span>28<spanclass=′latex−bold′>(B)</span>49<spanclass=′latex−bold′>(C)</span>98<spanclass=′latex−bold′>(D)</span>an odd multiple of 7 greater than 49<spanclass=′latex−bold′>(E)</span>an even multiple of 7 greater than 98