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equal angles wanted, AH =3KH on altitude AH, circumcircle related

Source: Ukraine TST 2018 p10

April 29, 2020
geometrycircumcirclemidpointsaltitudeequal angles

Problem Statement

Let ABCABC be a triangle with AHAH altitude. The point KK is chosen on the segment AHAH as follows such that AH=3KHAH =3KH. Let OO be the center of the circle circumscribed around by triangle ABC,MABC, M and NN be the midpoints of ACAC and AB respectively. Lines KOKO and MNMN intersect at the point ZZ, a perpendicular to OKOK passing through point ZZ intersects lines ACAC and ABAB at points XX and YY respectively. Prove that XKY=CKB\angle XKY =\angle CKB.