MathDB
Problems
Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 8
1989 AMC 8
8
1989 AJHSME Problem 8
1989 AJHSME Problem 8
Source:
June 25, 2011
Problem Statement
(
2
×
3
×
4
)
(
1
2
+
1
3
+
1
4
)
=
(2\times 3\times 4)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right) =
(
2
×
3
×
4
)
(
2
1
+
3
1
+
4
1
)
=
(A)
1
(B)
3
(C)
9
(D)
24
(E)
26
\text{(A)}\ 1 \qquad \text{(B)}\ 3 \qquad \text{(C)}\ 9 \qquad \text{(D)}\ 24 \qquad \text{(E)}\ 26
(A)
1
(B)
3
(C)
9
(D)
24
(E)
26
Back to Problems
View on AoPS