MathDB
Putnam 2016 A1

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December 4, 2016
PutnamPutnam 2016Putnam easyPutnam number theory

Problem Statement

Find the smallest positive integer jj such that for every polynomial p(x)p(x) with integer coefficients and for every integer k,k, the integer p(j)(k)=djdxjp(x)x=kp^{(j)}(k)=\left. \frac{d^j}{dx^j}p(x) \right|_{x=k} (the jj-th derivative of p(x)p(x) at kk) is divisible by 2016.2016.