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2024 AIME
13
2023 AIME II P8 all over again
2023 AIME II P8 all over again
Source: 2024 AIME II Problem 13
February 8, 2024
AIME
AIME I
AIME II
Problem Statement
Let
ω
≠
1
\omega \ne 1
ω
=
1
be a
13
13
13
th root of unity. Find the remainder when
∏
k
=
0
12
(
2
−
2
ω
k
+
ω
2
k
)
\prod_{k=0}^{12} \left(2 - 2\omega^k + \omega^{2k} \right)
k
=
0
∏
12
(
2
−
2
ω
k
+
ω
2
k
)
is divided by
1000
1000
1000
.
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