MathDB
(2^1998)(5^1998)

Source: 0

April 23, 2009
floor functionlogarithms

Problem Statement

Let A A, B B be the number of digits of 21998 2^{1998} and 51998 5^{1998} in decimal system. A \plus{} B \equal{} ?
<spanclass=′latex−bold′>(A)</span> 1998<spanclass=′latex−bold′>(B)</span> 1999<spanclass=′latex−bold′>(C)</span> 2000<spanclass=′latex−bold′>(D)</span> 3996<spanclass=′latex−bold′>(E)</span> 3998<span class='latex-bold'>(A)</span>\ 1998 \qquad<span class='latex-bold'>(B)</span>\ 1999 \qquad<span class='latex-bold'>(C)</span>\ 2000 \qquad<span class='latex-bold'>(D)</span>\ 3996 \qquad<span class='latex-bold'>(E)</span>\ 3998
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