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2007 Moldova National Olympiad
12.7
Weak Stirling limit
Weak Stirling limit
Source: Moldova MO 2007 12th grade day II problem 7
March 4, 2007
limit
logarithms
integration
calculus
calculus computations
Problem Statement
Find the limit
lim
n
→
∞
(
2
n
+
3
)
(
2
n
+
4
)
…
(
3
n
+
3
)
n
+
1
n
+
1
\lim_{n\to \infty}\frac{\sqrt[n+1]{(2n+3)(2n+4)\ldots (3n+3)}}{n+1}
n
→
∞
lim
n
+
1
n
+
1
(
2
n
+
3
)
(
2
n
+
4
)
…
(
3
n
+
3
)
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