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[x] {x} = 1999x (VI Soros Olympiad 1990-00 R1 9.2)

Source:

May 27, 2024
algebranumber theoryfractional partfloor function

Problem Statement

Solve the equation [x]{x}=1999x[x]\{x\} = 1999x, where [x][x] denotes the largest integer less than or equal to xx, and {x}=xāˆ’[x]\{x\} = x -[x]