MathDB
11st ibmo - costa rica 1996/q2.

Source: Spanish Communities

April 23, 2006
geometrycircumcircle

Problem Statement

Let ABC\triangle{ABC} be a triangle, DD the midpoint of BCBC, and MM be the midpoint of ADAD. The line BMBM intersects the side ACAC on the point NN. Show that ABAB is tangent to the circuncircle to the triangle NBC\triangle{NBC} if and only if the following equality is true: BMMN=(BC)2(BN)2.\frac{{BM}}{{MN}} =\frac{({BC})^2}{({BN})^2}.