MathDB
2018 = A^5 + B^5 + C^5 + D^5 + E^5, 2018 = A^5 + B^5 + C^5 + D^5

Source: Lusophon 2019 CPLP P5

December 31, 2019
number theorySum of powers

Problem Statement

a) Show that there are five integers A,B,C,DA, B, C, D, and EE such that 2018=A5+B5+C5+D5+E52018 = A^5 + B^5 + C^5 + D^5 + E^5
b) Show that there are no four integers A,B,CA, B, C and DD such that 2018=A5+B5+C5+D52018 = A^5 + B^5 + C^5 + D^5