MathDB
OMK 2010

Source:

June 4, 2011
geometryincenter

Problem Statement

Let ABCABC be a triangle in which AB=ACAB=AC. A point II lies inside the triangle such that ABI=CBI\angle ABI=\angle CBI and BAI=CAI\angle BAI=\angle CAI. Prove that BIA=90o+C2\angle BIA=90^o+\dfrac{\angle C}{2}