21:["$","div",null,{"data-slot":"card","className":"bg-card text-card-foreground flex flex-col gap-6 rounded-xl border py-6 shadow-sm w-full","children":[["$","div",null,{"data-slot":"card-header","className":"@container/card-header grid auto-rows-min grid-rows-[auto_auto] items-start gap-2 px-6 has-data-[slot=card-action]:grid-cols-[1fr_auto] [.border-b]:pb-6 space-y-4","children":[["$","div",null,{"className":"flex justify-between items-start gap-4","children":[["$","div",null,{"className":"space-y-2","children":[["$","div",null,{"data-slot":"card-title","className":"text-2xl font-bold","children":"Colouring a complete graph"}],["$","p",null,{"className":"text-sm text-muted-foreground","children":["Source: ","Baltic Way 2017, Problem 7"]}]]}],["$","div",null,{"className":"text-sm text-muted-foreground whitespace-nowrap","children":"November 26, 2017"}]]}],["$","div",null,{"className":"flex flex-wrap gap-2","children":[["$","span","21",{"data-slot":"badge","className":"inline-flex items-center justify-center rounded-full border px-2 py-0.5 text-xs font-medium w-fit whitespace-nowrap shrink-0 [&>svg]:size-3 gap-1 [&>svg]:pointer-events-none focus-visible:border-ring focus-visible:ring-ring/50 focus-visible:ring-[3px] aria-invalid:ring-destructive/20 dark:aria-invalid:ring-destructive/40 aria-invalid:border-destructive transition-[color,box-shadow] overflow-hidden border-transparent bg-secondary text-secondary-foreground [a&]:hover:bg-secondary/90","children":"combinatorics"}],["$","span","1030",{"data-slot":"badge","className":"inline-flex items-center justify-center rounded-full border px-2 py-0.5 text-xs font-medium w-fit whitespace-nowrap shrink-0 [&>svg]:size-3 gap-1 [&>svg]:pointer-events-none focus-visible:border-ring focus-visible:ring-ring/50 focus-visible:ring-[3px] aria-invalid:ring-destructive/20 dark:aria-invalid:ring-destructive/40 aria-invalid:border-destructive transition-[color,box-shadow] overflow-hidden border-transparent bg-secondary text-secondary-foreground [a&]:hover:bg-secondary/90","children":"Graph coloring"}],["$","span","70",{"data-slot":"badge","className":"inline-flex items-center justify-center rounded-full border px-2 py-0.5 text-xs font-medium w-fit whitespace-nowrap shrink-0 [&>svg]:size-3 gap-1 [&>svg]:pointer-events-none focus-visible:border-ring focus-visible:ring-ring/50 focus-visible:ring-[3px] aria-invalid:ring-destructive/20 dark:aria-invalid:ring-destructive/40 aria-invalid:border-destructive transition-[color,box-shadow] overflow-hidden border-transparent bg-secondary text-secondary-foreground [a&]:hover:bg-secondary/90","children":"graph theory"}]]}]]}],["$","div",null,{"data-slot":"card-content","className":"px-6 space-y-8","children":[["$","section",null,{"className":"space-y-3","children":[["$","h2",null,{"className":"text-lg font-semibold","children":"Problem Statement"}],["$","div",null,{"className":"prose dark:prose-invert max-w-none bg-muted/30 p-4 rounded-lg","children":["$","div",null,{"className":"latex","children":["$","span",null,{"className":"__Latex__","dangerouslySetInnerHTML":{"__html":"Each edge of a complete graph on

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vertices is coloured either red or blue. It is allowed to choose a non-monochromatic triangle and change the colour of the two edges of the same colour to make the triangle monochromatic.\nProve that by using this operation repeatedly it is possible to make the entire graph monochromatic.\n(A complete graph is a graph where any two vertices are connected by an edge.)"}}]}]}]]}],"$L23"]}]]}]