MathDB
Classic Problem

Source:

March 25, 2006

Problem Statement

At his usual rate a man rows 1515 miles downstream in five hours less time than it takes him to return. If he doubles his usual rate, the time downstream is only one hour less than the time upstream. In miles per hour, the rate of the stream's current is: (A) 2(B) 52(C) 3(D) 72(E) 4\text{(A)} \ 2 \qquad \text{(B)} \ \frac52 \qquad \text{(C)} \ 3 \qquad \text{(D)} \ \frac72 \qquad \text{(E)} \ 4
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