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Today's calculation of Integral 3

Source: created by kunny

May 2, 2005
calculusintegrationtrigonometrylogarithmscalculus computations

Problem Statement

Calculate the following indefinite integrals. [1] ∫sin⁡xsin⁡2xdx\int \sin x\sin 2x dx [2] ∫e2xex−1dx\int \frac{e^{2x}}{e^x-1}dx [3] ∫tan⁡2xcos⁡2xdx\int \frac{\tan ^2 x}{\cos ^2 x}dx [4] ∫ex+e−xex−e−xdx\int \frac{e^x+e^{-x}}{e^x-e^{-x}}dx [5] ∫exex+1dx\int \frac{e^x}{e^x+1}dx
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