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Feet of altitudes and circumcircle of a triangle ABC

Source: problem 5 (G1) of QEDMO 1; classical origins

November 7, 2005
geometrycircumcircletrigonometrygeometry proposed

Problem Statement

Let ABCABC be a triangle, and let CC^{\prime} and AA^{\prime} be the feet of its altitudes issuing from the vertices CC and AA, respectively. Denote by PP the midpoint of the segment CAC^{\prime}A^{\prime}. The circumcircles of triangles ACPAC^{\prime}P and CAPCA^{\prime}P have a common point apart from PP; denote this common point by QQ. Prove that: (a) The point QQ lies on the circumcircle of the triangle ABCABC. (b) The line PQPQ passes through the point BB. (c) We have AQCQ=ABCB\frac{AQ}{CQ}=\frac{AB}{CB}. Darij