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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
6
Today's calculation of Integral 6
Today's calculation of Integral 6
Source:
May 5, 2005
calculus
integration
trigonometry
logarithms
derivative
calculus computations
Problem Statement
Calculate the following indefinite integrals. [1]
∫
sin
x
cos
3
x
d
x
\int \sin x\cos ^ 3 x dx
∫
sin
x
cos
3
x
d
x
[2]
∫
d
x
(
1
+
x
)
x
d
x
\int \frac{dx}{(1+\sqrt{x})\sqrt{x}}dx
∫
(
1
+
x
)
x
d
x
d
x
[3]
∫
x
2
x
3
+
1
d
x
\int x^2 \sqrt{x^3+1}dx
∫
x
2
x
3
+
1
d
x
[4]
∫
e
2
x
−
3
e
x
e
x
d
x
\int \frac{e^{2x}-3e^{x}}{e^x}dx
∫
e
x
e
2
x
−
3
e
x
d
x
[5]
∫
(
1
−
x
2
)
e
x
d
x
\int (1-x^2)e^x dx
∫
(
1
−
x
2
)
e
x
d
x
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