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x^2/16 + y^2/ 4 =1 , (x -2)^2 + (y - 1)^2 = 5

Source: Spanish Mathematical Olympiad 1979 P1

December 23, 2022
conicsellipseanalytic geometry

Problem Statement

Calculate the area of the intersection of the interior of the ellipse x216+y24=1\frac{x^2}{16}+ \frac{y^2}{4}= 1 with the circle bounded by the circumference (x−2)2+(y−1)2=5(x -2)^2 + (y - 1)^2 = 5.
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