MathDB
2004 Algebra #3

Source:

December 26, 2011
floor function

Problem Statement

Compute ⌊200532003⋅2004−200332004⋅2005⌋ \left\lfloor \dfrac {2005^3}{2003 \cdot 2004} - \dfrac {2003^3}{2004 \cdot 2005} \right\rfloor
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