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Circle tangent to n circles derived from a bicentric n-gon

Source: Brazilian Mathematical Olympiad 2021, Level 3, Problem 6

February 8, 2022
geometrybicentric polygonconvex polygonInscribed circlecircumscribedtangent circles

Problem Statement

Let n5n \geq 5 be integer. The convex polygon P=A1A2AnP = A_{1} A_{2} \ldots A_{n} is bicentric, that is, it has an inscribed and circumscribed circle. Set Ai+n=AiA_{i+n}=A_{i} to every integer ii (that is, all indices are taken modulo nn). Suppose that for all i,1ini, 1 \leq i \leq n, the rays Ai1AiA_{i-1} A_{i} and Ai+2Ai+1A_{i+2} A_{i+1} meet at the point BiB_{i}. Let ωi\omega_{i} be the circumcircle of BiAiAi+1B_{i} A_{i} A_{i+1}. Prove that there is a circle tangent to all nn circles ωi\omega_{i}, 1in1 \leq i \leq n.