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diophantine xyz = 2(x + y + z) 2021 Malaysia IMONST 1 Senior P12

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September 21, 2021
number theoryDiophantine equationdiophantine

Problem Statement

Determine the number of positive integer solutions (x,y,z)(x,y, z) to the equation xyz=2(x+y+z)xyz = 2(x + y + z).