MathDB
Maya's Divisors

Source: AIME 2010I Problem 1

March 17, 2010
probabilityAMCAIMEnumber theoryrelatively prime

Problem Statement

Maya lists all the positive divisors of 20102 2010^2. She then randomly selects two distinct divisors from this list. Let p p be the probability that exactly one of the selected divisors is a perfect square. The probability p p can be expressed in the form mn \frac{m}{n}, where m m and n n are relatively prime positive integers. Find m \plus{} n.