MathDB
a cute geometric inequality

Source: Moldova TST Problem 3, day 3

March 31, 2015
inequalitiesgeometric inequality

Problem Statement

The tangents to the inscribed circle of ABC\triangle ABC, which are parallel to the sides of the triangle and do not coincide with them, intersect the sides of the triangle in the points M,N,P,Q,R,SM,N,P,Q,R,S such that M,S(AB)M,S\in (AB), N,P(AC)N,P\in (AC), Q,R(BC)Q,R\in (BC). The interior angle bisectors of AMN\triangle AMN, BSR\triangle BSR and CPQ\triangle CPQ, from points A,BA,B and respectively CC have lengths l1l_{1} , l2l_{2} and l3l_{3} .\\ Prove the inequality: 1l12+1l22+1l3281p2\frac {1}{l^{2}_{1}}+\frac {1}{l^{2}_{2}}+\frac {1}{l^{2}_{3}} \ge \frac{81}{p^{2}} where pp is the semiperimeter of ABC\triangle ABC .