MathDB
x - \sqrt{x^2-a^2} = (x-a)^2}/2(x+a) (V Soros Olympiad 1998-99 Round 2 11.3)

Source:

May 25, 2024
algebra

Problem Statement

For each value of parameter aa, solve the the equation xx2a2=(xa)22(x+a) x - \sqrt{x^2-a^2} = \frac{(x-a)^2}{2(x+a)}